what do you mean with “I set xmpp.domain to 192.168.1.130”??
my problem is, that i have activeted media proxy in openfire, but I don’t know how to integrate it in my client? do I have to change the host-url of my client? how does my client know to use the proxy?
when your clients need to use media proxy, one client need to send xmpp request message like below
Entity Requests a candidate from Host
<iq type=‘get’ id=‘cand1’ to=‘rtpbridge.serverdomain’>
<rtpbridge xmlns=‘The Jive Employee Engagement Platform’ sid=‘session1’>
<candidate/>
</rtpbridge >
</iq>
and your cliend will receive Host Returns Candidates to Entity
<iq type=‘result’ id=‘cand1’>
<rtpbridge xmlns=‘The Jive Employee Engagement Platform’ sid=‘session1’>
<candidate name=‘myvoicedata’ ip=‘200.10.11.104’ porta=‘13540’ portb=‘12555’ pass=‘pxpxpx’/>
</rtpbridge >
</iq>
Now your openfire server will open 4 udp ports are (13540,13541) and (12555,12556)
when one user send udp packet to your openfire server in port 13540, another user can receive data by read from port 13541
and ports (12555,12556) working like port (13540,13541)
do I have to make a seperate configuration to my client to use the media proxy or should work this automatically when I enabled the media proxy in openfire?